Answer:
[tex]a=4.8m/s^2[/tex]
Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:
[tex]a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)[/tex]
The purpose here is derive x(t) twice as follows:
[tex]a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2[/tex]
Thus, the acceleration turns out 4.8 meters per squared seconds.
Best regards.
