Given :
Two hockey of same mass.
One is travelling at a speed of 2 m/s.
Other is in rest or 0 m/s.
To Find :
The momentum of this group of objects.
Solution :
Since , no external force is applied , so momentum will remains same :
Momentum of group of objects ,
[tex]M = mv_1^2+mv_2^2\\\\M = 0.25\times 2^2+0.25\times 0\\\\M=1 \ kg \ m/s[/tex]
Therefore , momentum of the system is 1 kg m/s.
Hence , this is the required solution.