Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. How
far away must he and Marty stand to allow the car to accelerate from rest to a speed
of 39.2 m/s?

Respuesta :

Answer:

The value  is  [tex]s = 306.6 \ m[/tex]

Explanation:

From the question we are told that

   The  acceleration is [tex]a = 2.52 \ m/s[/tex]

    The speed to attain is [tex]v = 39.2 \ m/s[/tex]

Generally the time taken is mathematically represented as

        [tex]t = \frac{v}{a}[/tex]

=>    [tex]t = \frac{39.2}{2.52}[/tex]

=>    [tex]t= 15.6 \ s[/tex]

Generally from the kinematic equation we have that

      [tex]s = ut + \frac{1}{2}at^2[/tex]

Here the initial  velocity is  zero i.e  u =  0 \  m/s (it started from rest)

So

     [tex]s = 0* 15.6 + \frac{1}{2} * 2.52 * (15.6)^2[/tex]

=>  [tex]s = 306.6 \ m[/tex]