Let x be the first integer
, y be the second integer
, and z be the third integer
x < y < z < 25
We know that
Median=13
Median=(x+y+z)/3
13=(x+y+z)/3
x+y+z=39------> equation 1
Range=10
The range is the difference between the largest number within the set and the smallest number in the set
So range=z-x
z-x=10------> z=x+10-----> equation 2
to find the solution we will assume different values of x (See the attached table)
terms
x < y < z < 25
z=x+10
y=39-z-x
The solution can be
7,15,17
8,13,18
9,11,19
hope it helps!
