Respuesta :
Answer:
a.) the average speed of the aircraft in miles per hour
115.76 miles/ hour
b.) the fuel consumption in miles per pound of fuel
(assume a density of 0.70 g/mL for the fuel.)
2.8 miles/Ib of fuel
Step-by-step explanation:
A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:
flight distance: 25,012 miles
flight time: 9 days, 3 min., 44 seconds
fuel capacity: nearly 9000 lbs.
fuel remaining at the end of flight: 14 gal.
To the maximum number of significant figure permitted, calculate:
a.) the average speed of the aircraft in miles per hour
Step 1
We convert the time to hours
flight time: 9 days, 3 min., 44 seconds
1 day = 24 hours
9 days =
24 × 9
= 216 hours
60 mins = 1 hour
3 mins =
3/60 = 1/20 = 0.05 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 hour = 60 × 60 = 3600 seconds
If 3600 seconds = 1 hour
44 seconds =
= 44/3600
= 0.0122222222 hours
Total number of hours spent = (216 + 0.05 + 0.0122222222) hours
= 216.06222222 hours
Speed = Distance/Time
= flight distance: 25,012 miles
Speed = 25,012 miles/ 216.06222222hours
= 115.76294895 miles/ hour
Approximately = 115.76 miles/ hour
b.) the fuel consumption in miles per pound of fuel
(assume a density of 0.70 g/mL for the fuel.)
Step 1
We determine how much fuel is used
We have 14 gallons of fuel left over
1 gallon = 3.785 litres
14 gallons =
Cross Multiply
14 gallons × 3.785 liters/1 gallon
= 52.9958 liters
Note that density of fuel =
0.70 g/ml
1 gram / millilitre = 1 kilogram / litre
Hence, 0.7g/ml = 0.7 kg/L
Hence,the mass of fuel left = 52.9958 liters * 0.7 = 37.09706kg
1 kilogram = 2.205 pounds
37.09706kg =
37.09706kg × 2.205 pounds
= 81.7990173 lbs
Since the full capacity = 9000 lbs
The fuel used = 9000 - 81.7990173 lbs
= 8918.2009827 lbs
Hence, fuel consumption is
Distance/ amount of fuel used
25012/8918.2009827 lbs = 2.8046015164 miles/lb of fuel
Approximately = 2.8 miles/Ib of fuel
