[tex]\text {Hello! To solve for x you must...}[/tex]
[tex]\text {Simplify the Equation (KCC):}[/tex]
[tex]\text {Keep: 4/3x}[/tex]
[tex]\text {Change: - into +}[/tex]
[tex]\text {Change: 4 into -4}[/tex]
[tex]\text {Switch:}[/tex]
[tex]\text {5+x changes into x+5}[/tex]
[tex]\text {Your new problem should be 4/3x-4=x+5}[/tex]
[tex]\text {The Next Step is to Subtract x:}[/tex]
[tex]\text {4/3x-4-x=x+5-x}[/tex]
[tex]\text {1/3-4=5}[/tex]
[tex]\text {Next you would want to add 4}[/tex]
[tex]\text {Q: Why would we add 4 instead of subtracting 4?}[/tex]
[tex]\text {A: Because we need 4 to equal to 0. We will add 4 to cross out 4. So -4+4 will equal 0.}[/tex]
[tex]\text {1/3-4+4=5+4}[/tex]
[tex]\text {1/3x=9}[/tex]
[tex]\text {Your Final Step will be to Multiply 3 on both sides:}[/tex]
[tex]\text {Q: Why do we multiply 3?}[/tex]
[tex]\text {A: Because if we multiply 1 it won't really equal to anything. So we multiply 3 to get x}[/tex][tex]\text {by itself.}[/tex]
[tex]\text 3*(1/3x)=(3)*(9)[/tex]
[tex]\text {Note: 3 makes the fraction cancel out. So now x is by itself.}[/tex]
[tex]\text {Your Final Answer is...}[/tex]
[tex]\fbox {x=27}[/tex]
[tex]\text {Best of Luck!}[/tex]
[tex]\text {-LimitedX}[/tex]
