Marin writes the functions m(x) = StartFraction 3 x Over x + 7 EndFraction and n(x) = StartFraction 7 x Over 3 minus x EndFraction. Which equation must be true for m(x) and n(x) to be inverse functions?

Marin writes the functions mx StartFraction 3 x Over x 7 EndFraction and nx StartFraction 7 x Over 3 minus x EndFraction Which equation must be true for mx and class=
Marin writes the functions mx StartFraction 3 x Over x 7 EndFraction and nx StartFraction 7 x Over 3 minus x EndFraction Which equation must be true for mx and class=

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Idea63

Answer: B

Step-by-step explanation:

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The functions m(x) and n(x) are inverses of each other and this is shown by the equation in option B.

What is an Inverse Function?

To find an inverse function of a function (x,y), the y and x are interchanged and the equation is then solved for y.

The functions are :

[tex]\rm m(x) = \dfrac{3x}{x+7}[/tex]

[tex]\rm n(x) = \dfrac{7x}{3-x}[/tex]

The inverse of the function m(x) will be determined to check if both the functions  given are inverse of each other

Let m(x) = y

[tex]\rm y= \dfrac{3x}{x+7}\\\\\\On \; Interchanging \ ; x \;a nd\; y\\\\x = \dfrac{3y}{y+7}[/tex]

As n(x) is the inverse of m(x) ,

 [tex]\rm y = n(x) = \dfrac{7x}{3-x}[/tex]

Equation 1 is

[tex]\rm x = \dfrac{3( \dfrac{7x}{3-x})}{\dfrac{7x}{3-x} +7}\\[/tex]

same goes for function n(x)

[tex]\rm x = \dfrac{7y}{3-y}\\\\\\Equation \; 2 \; is\\x = \dfrac{7( \dfrac{3x}{x+7})}{3 - (\dfrac{3x}{x+7})}[/tex]

From equation 1 and 2

[tex]\rm x = \dfrac{3( \dfrac{7x}{3-x})}{\dfrac{7x}{3-x} +7} = \dfrac{7( \dfrac{3x}{x+7})}{3 - (\dfrac{3x}{x+7})}[/tex]

Therefore, the correct option is B

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