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A dog walks 8.0 meters due north and then 6.0 meters due east.







Determine the magnitude of the dog's total displacement to the nearest tenths place.

Respuesta :

abidemiokin

Answer:

10.0m

Explanation:

The displacement of the dog is the distance moved in a specified direction. It will be gotten using pythagoras theorem as shown;

d² = 8²+6²

d² =64+36

d² = 100

square root both sides

√d² = √100

d = 10m

Hence the displacement of the dog to the nearest tenth is 10.0m

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