Answer:
Explanation:
For the questions we will be using the formula;
acceleration = change in velocity/Time
acceleration = v-u/t
v is the final velocity
u is the initial velocity
t is the time
1) v = 15m/s, u = 2m/s t = 15s
a = 15-2/15
a = 13/15
a = 0.87m/s²
Their acceleration was 0.87m/s²
2) u = 10m/s, v = 45m/s, t = 1.75s
a = 45-10/1.75
a = 35/1.75
a = 35/(175/100)
a = 35×100/175
a = 3500/175
a = 20m/s²
3) u = 35m/s, v = 0m/s (comes to a stop), t = 1.25m/s
a = 0-35/1.25
a = -35/1.25
a = -28m/s²
The acceleration of the car is -28m/s²
4) v =55m/s, u = 0m/s t = 12s
a = 55-0/12
a = 55/12
a = 4.58m/s²
His acceleration when he got to the turn is 4.58m/s²
5) u = 17m/s (starting velocity)
v = 0m/s (stopping velocity)
t = 4.5s
a = 0-17/4/5
a = -17/4.5
a = -3.78m/s²
The the acceleration of the ball was -3.78m/s²