Answer:
Step-by-step explanation:
1). Number of students in the survey = Total of frequencies
= 3 + 5 + 4 + 6 + 3 + 1
= 22
2). Range of number of pets = 6 - 1 = 5
3). Number of pets most student have = Highest frequency of the number of pets
= 4 pets
4). For the median number of pets,
Arrange the frequencies in the increasing order,
1, 3, 3, 4, 5, 6
Since number of terms are even, median of the data will be the average of middle two terms.
Middle terms of the frequencies are 3 and 4.
Therefore, average of these numbers = [tex]\frac{3+4}{2}=3.5[/tex]
Therefore, median number of pets = 3.5
