Given :
Distance of point P from the origin is , d = 9.83 mm .
To Find :
The electric field produced by this charge at point P , if charge is placed at origin .
Solution :
Let , charge on origin is q .
Electric field at point P is given by :
[tex]E=\dfrac{kq}{r^2}[/tex] ..... ( 1 )
Here , k is constant , [tex]k=9\times 10^{9}\ N \ m^2/C^2[/tex] .
Putting value of k and r in above equation , we get :
[tex]E=\dfrac{q\times 9\times 10^9}{(9.83\times 10^{-3})^2}\ N/C\\\\E=(9.31\times 10^{13})q\ N/C[/tex]
Hence , this is the required solution .
