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14-09-2016
Chemistry

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The specific heat of copper is 0.092 cal/g °C. If a 590 g copper pan is heated from a temperature of 25 °C to 180 °C, how many calories of heat energy will the copper pan absorb?

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18-09-2016

[tex]Q=cm \Delta T\\\\ c=0,092\frac{cal}{g^{o}C}\\ m=590g\\ \Delta T=180^{o}C-25^{o}C=155^{o}C\\\\ Q=0,092\frac{cal}{g^{o}C}*590g*155^{o}C=8413,4cal[/tex]

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