Answer:
a [tex]W_{3.5} = 490 \ J[/tex]
b [tex]W_{2.5} = 250 \ J[/tex]
Explanation:
Generally the force constant is mathematically represented as
[tex]k = \frac{F}{x}[/tex]
substituting values given in the question
=> [tex]k = \frac{16}{0.2}[/tex]
=> [tex]k = 80 \ N /m[/tex]
Generally the workdone in stretching the spring 3.5 m is mathematically represented as
[tex]W_{3.5} = \frac{1}{2} * k * (3.5)^2[/tex]
=> [tex]W_{3.5} = \frac{1}{2} * 80 * (3.5)^2[/tex]
=> [tex]W_{3.5} = 490 \ J[/tex]
Generally the workdone in compressing the spring 2.5 m is mathematically represented as
[tex]W_{2.5} = \frac{1}{2} * k * (2.5)^2[/tex]
=> [tex]W_{2.5} = \frac{1}{2} * 80 * (2.5)^2[/tex]
=> [tex]W_{2.5} = 250 \ J[/tex]
