Respuesta :
Answer:
The velocity is [tex]v = 6.66 \ m/s [/tex]
Henrietta is at distance [tex]s= 18.17 \ m[/tex] from the under the window
Explanation:
From the question we are told that
The speed of Henrietta is [tex]v= 2.70 \ m/s[/tex]
The height of the window from the ground is [tex]h = 36.5 \ m[/tex]
Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is
[tex]t = \sqrt{\frac{2 * h }{g} }[/tex]
=> [tex]t = \sqrt{\frac{2 * 36.5 }{9,8} }[/tex]
=> [tex]t = 2.73 \ s [/tex]
Generally the time taken for the lunch to reach Henrietta is mathematically represented as
[tex]T = t + t_1[/tex]
Here [tex]t_1[/tex] is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s
Now
[tex]T = 2.73 + 4[/tex]
=> [tex]T = 6.73 \ s [/tex]
Generally the distance covered by Henrietta before catching her lunch is
[tex]s= v * T[/tex]
=> [tex]s= 2.70 * 6.73[/tex]
=> [tex]s= 18.17 \ m[/tex]
Generally the speed with which Bruce threw her lunch is mathematically represented as
[tex]v = \frac{18.17}{2.73}[/tex]
[tex]v = 6.66 \ m/s [/tex]