Answer:
The power delivered when the filament temperature is 2000 K is 189.63 W.
Explanation:
Given;
initial temperature of the light bulb, T₁ = 1500 K
initial power delivered, P₁ = 60 W
Final temperature, T₂ = 2000 K
Final power delivered, P₂ = ?
Apply Stefan-Boltzmann law of radiation;
[tex]\frac{Q}{t} = \alpha \epsilon AT^4\\\\P = \alpha \epsilon AT^4\\\\\frac{P_1}{T_1^4} = \frac{P_2}{T_2^4}\\\\P_2 = \frac{P_1T_2^4}{T_1^4} \\\\P_2 = \frac{60*(2000)^4}{(1500)^4}\\\\ P_2 = 189.63 \ W[/tex]
Therefore, the power delivered when the filament temperature is 2000 K is 189.63 W.
