Answer:
0.257 L
Explanation:
The values missing in the question has been assumed with common sense so that the concept could be applied
Initial volume of the AICI3 solution [tex]=23.1 \mathrm{mL}[/tex]
Initial Molarity of the solution [tex]=833 \mathrm{mM}[/tex]
Final molarity of the solution [tex]=75.0 \mathrm{mM}[/tex]
Final volume of the solution [tex]=?[/tex]
From Law of Dilution, [tex]M_{f} V_{f}=M_{i} V_{i}[/tex]
[tex]\Rightarrow V_{f}=\frac{M_{i} V_{i}}{M_{f}}=\frac{833 \mathrm{mM} \times 23.1 \mathrm{mL}}{75.0 \mathrm{mM}}=256.564 \mathrm{mL}=0.256564 \mathrm{L}=0.257 L[/tex]
Final Volume of the solution [tex]=0.257[/tex]
