Answer:
a
[tex]H_1 = 0.0195 \ m [/tex]
[tex]H_2 = 0.0117 \ m [/tex]
b
Yes it is in conflict with Pascal's law
Explanation:
From the question we are told that
The surface tension is [tex]s = 0.07 \ N/m[/tex]
The contact angle is [tex]\theta = 10^o[/tex]
The density is [tex]\rho = 960 \ kg/m^3[/tex]
The first tube diameter is [tex]d_1 = 1.5mm = 1.5 *10^{-3} \ m[/tex]
The second tube diameter is [tex]d_2 = 2.5mm = 2.5 *10^{-3} \ m[/tex]
The first tube radius is [tex]r_1 = \frac{1.5 *10^{-3}}{2} = 0.75 *10^{-3} \ m[/tex]
The first tube radius is [tex]r_1 = \frac{2.5 *10^{-3}}{2} = 1.5 *10^{-3} \ m[/tex]
Generally capillary rise is mathematically represented as
[tex]H = \frac{2 * s * cos(\theta)}{ \rho * g * r }[/tex]
For first tube
[tex]H_1 = \frac{2 * 0.07 * cos(10)}{ 960 * 9.8 * 0.75 *10^{-3} }[/tex]
[tex]H_1 = 0.0195 \ m [/tex]
For second tube
[tex]H_2 = \frac{2 * 0.07 * cos(10)}{ 960 * 9.8 * 1.5 *10^{-3} }[/tex]
[tex]H_2 = 0.0117 \ m [/tex]
From the values obtained we see that
[tex]H_1 \ne H_2[/tex]
Which means that Pascal’s law has been violated
