The relationship between voltage, E, current, I, and resistance, Z, is given by the equation E = IZ. If a circuit has a current I = 3 + 2i and a resistance Z = 2 – i, what is the voltage of the circuit?. a. 4 – i. b. 4 + i. c. 8 + i. d. 8 + 7i

Respuesta :

The correct answer is C. 8 + i

By definition, we have to:

[tex] E = IZ
[/tex]

Where,

E: voltage

I: current

Z: Resistance

To calculate the voltage value, we must replace the following values in the given equation:

[tex] I = 3 + 2i

Z = 2 - i
[/tex]

We have then:

[tex] E = (3 + 2i) (2 - i)
[/tex]

Making the product of complex numbers we have:

[tex] E = (3 * 2 - 3i) + (4i - 2i ^ 2)

E = (6 - 3i) + (4i - 2 (-1))

E = (6 - 3i) + (4i +2)
[/tex]

[tex] E = (6 + 2) + (4-3) i

E = 8 + i
[/tex]

Answer:

the voltage of the circuit is:

[tex] E = 8 + i
[/tex]

option C