Answer:
a. [tex]Ca(NO_3)_2(s)\rightarrow Ca^{2+}+2NO_3^-[/tex]
b. [tex]Na_3PO_4(s)\rightarrow 3Na^{+}+PO_4^{-3}[/tex]
Explanation:
Hello,
In this case, considering that the dissolution reaction of a solid in aqueous solutions involve the dissociation (separation) of both its cation and anion for the required salts we write:
a. [tex]Ca(NO_3)_2(s)\rightarrow Ca^{2+}+2NO_3^-[/tex]
b. [tex]Na_3PO_4(s)\rightarrow 3Na^{+}+PO_4^{-3}[/tex]
Thus, a two is required for nitrate anions in a. in order to balance it at the reactant and a three is required for sodium cations in b. in order to balance it as well.
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