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A single household circuit is connected to three electrical outlets (all in parallel). The outlets are connected to three devices: an 800-W electric kettle, a 60-W trouble light, and a 1,000-W toaster oven. If all three appliances operate at the same time, will the 15-amp fuse of the circuit trip? yes or no ?

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AL2006
The total power consumption when all three of them are turned on is 1,860 watts. Power=(voltage)x(current). If the service to the household is 120 volts, then the current will be 1860/120=15.5A, which the fuse or breaker will not allow, and they will blow/trip. If the house is in South America or Europe, and the mains service is 240 volts, then the current will be 1860/240= 7.75 Amp, and the fuse or breaker will be 'cool' with that.

Power (Watts) = Voltage (Volts) times the Current in (Amps). 
so
P=I*E Or
 (P/E) = I Or (P/I) = E 
So a 2,000 W dryer operating at 240V will draw 8.3 Amps. 
But a 2,000 W dryer operating at 120V will draw 16.7 Amps. 
so
 800W + 60W +1,000W total 1,860W 
applying formula
Using (P/E) = I 
1,860W/120V = 15.5A 
yep, it could trip a 15.0 A breaker
hope it helps

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