Given :
A restaurant had 3 full boxes of spoons and 4/6 of a box.
Each full box weighed 2 kilograms .
To Find :
The combined weight of the boxes the restaurant has.
Solution :
Mass of 1 box is 2 kg .
So , mass of 4/6 of a box is 4/3 kg .
Total mass :
[tex]M=3\times \text{Mass of one full box }+ \text{Mass of 4/6 of a box}\\\\M=(3\times 2) + \dfrac{4}{3}\\\\M=7.33\ kg[/tex]
Therefore , the combined weight of the boxes the restaurant has is 7.33 kg.
Hence , this is the required solution .
