The question is incomplete; the complete question is;
A chemist must dilute 99.4 mL of 152 mM aqueous potassium dichromate (K_2Cr_2O_7) solution until the concentration falls to 55.0 mM He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.
Answer:
0.275 L
Explanation:
From C1V1 = C2V2
Where;
C1= initial concentration of the solution 152 × 10^-3 M
V1= initial volume of the solution = 99.4 × 10^-3 L
C2 = concentration after dilution = 55 × 10^-3 M
V2 = volume after dilution = the unknown
V2 = C1 V1/C2
V2 = 152 × 10^-3 × 99.4 × 10^-3 / 55 × 10^-3
V2 = 0.275 L
