cosec t(heta) = 13/12 1/sin t = 13/12 sin t = 12/13 cos t = √ (1 - (12/13)² ) = √ ( 1 - 144/169 ) = √25/169 cos t = 5/13 tan t = sin t/ cos t = (12/13) / (5/13) = 12/5 sec t = 1 / cos t = 13/5 Answer: A ) and B ) are correct: tan theta = 12/5 and sin theta = 12/13
