Respuesta :

sebassandin

Answer:

b) K3PO4

Explanation:

Hello,

In this case, since the van't Hoff factor for ionizing solutes equals the number of ionized particles (ions), the van't Hoff factor for each salt is:

a) CaCl2 : i=3 since two chloride anions and one calcium cation are ionized.

b) K3PO4 : i=4 since one phosphate anion and three potassium cations are ionized.

c) Li2CO3 : i=3 since one carbonate anions and two lithium cations are ionized.

d) NaNO3: i=2 since one nitrate anion and one sodium cation are ionized.

Therefore, b) K3PO4 has the largest van't Hoff factor as more ions are formed during its dissolution.

Best regards.

b) K₃PO₄

Van’t Hoff factor

  • The relationship between the actual number of moles of solute added to form a solution and the apparent number as determined by colligative properties is called the van’t Hoff factor ( i )
  • As the solute concentration increases the van’t Hoff factor decreases.

Let's look for all options one by one:

a) CaCl₂ : i=3 since two chloride anions and one calcium cation are ionized.

b) K₃PO₄ : i=4 since one phosphate anion and three potassium cations are ionized.

c) Li₂CO₃ : i=3 since one carbonate anions and two lithium cations are ionized.

d) NaNO₃: i=2 since one nitrate anion and one sodium cation are ionized.

Therefore, K₃PO₄ has the largest van't Hoff factor as more ions are formed during its dissolution.

Learn more:

brainly.com/question/22047232

Otras preguntas