The conversion from g to kg and cm to m only involves powers of 10:
[tex]\left(4.42\times10^{-2}\dfrac{\rm g}{\mathrm{cm}^3}\right)\left(\dfrac1{10^3}\dfrac{\rm kg}{\rm g}\right)\left(10^2\dfrac{\rm cm}{\rm m}\right)^3=4.42\times10^1\dfrac{\rm kg}{\mathrm m^3}[/tex]
so the answer is B.
