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A single-lane street 10ft wide goes through a semicircular tunnel with radius 9ft. How high is the tunnel at the edge of each of the lane? Round off to the 2 decimal places

Respuesta :

Answer:

7.48 feet

Step-by-step explanation:

To solve this question, we use this equation:

a² + b² = r²

r = 9 feet

Step 1

We find a

2a = Width of the semi circular tunnel

= 10 feet

a = 10/2

a = 5 feet

Step 2

We solve for b

b = Highest of the tunnel at the edge of the lane

a² + b² = r²

5² + b² = 9²

b² = 9² - 5²

b = √81 - 25

b = √56

b = 7.4833147735 feet

Therefore, rounding off to 2 decimal places, the height of the tunnel at the edge of each lane is 7.48 feet

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