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Two identical pellet guns are fired simultaneously from the edge of a cliff. These guns impart an initial speed of 23.7 m/s to each pellet. Gun A is fired straight upward, with the pellet going up and then falling back down, eventually hitting the ground beneath the cliff. Gun B is fired straight downward. In the absence of air resistance, how long after pellet B hits the ground does pellet A hit the ground

Respuesta :

Answer:

Ta - Tb = 4.84 sec (approx)

Explanation:

Time taken by A = Time taken By B + Extra time

Ta - Tb = T

We know that

Time (T) = [v-u] /a ...................[a=9.8 m/s²]

So,

Ta - Tb = [v-u] /a

Ta - Tb = [-23.7-23.7] /9.8

Ta - Tb = 4.8367 sec

Ta - Tb = 4.84 sec (approx)

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