Given :
A population of protozoa develops with a constant relative growth rate of 0.4142 per member per day.
On day zero the population consists of five members.
Differential equation : [tex]\dfrac{dP}{dt}=0.4142P[/tex]
To Find :
The population size after eight days.
Solution :
Rate of growth , R = 0.4142 .
Now ,
Differential equation is :
[tex]\dfrac{dP}{dt}=0.4142P\\\\P_n=Ce^{0.4142n}[/tex]
For n = 0 .
[tex]5=C(1)\\C=5[/tex]
So ,the relation is [tex]P_n=5e^{0.4142n}[/tex] .
Putting n = 8 .
[tex]P_8=5e^{0.4142\times 8}\\\\P_8=137.42[/tex]
Hence , this is the required solution .
