Respuesta :
Answer:
1.12M
Explanation:
The initial concentration of the HCl solution is 3.99M. You are doing 2 dilutions:
In the first you take 326mL and dilute the solution to 976mL; that means you are diluting the solution:
976mL / 326mL = 2.99 times.
The concentration of this solution is:
3.99M / 2.99 = 1.33M
Now, in the second dilution, you take 100mL of the diluted solution and dilute it to 119mL. The concentration of this final solution is:
119mL / 100mL = 1.19 times.
1.33M / 1.19 =
1.12M
The final concentration of hydrochloric acid present is 1.11 M.
- In the first dilution;
M1V1 = M2V2
M2 = 3.99 M × 326 ml/976 ml
M2 = 1.33 M
In the second dilution:
M1V1 = M2V2
M2 = 1.33 M × 100.00 ml/119 ml
M2 = 1.11 M
Hence, the final concentration of hydrochloric acid present is 1.11 M.
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