Suppose that the number of miles that an EV battery (electric vehicle) can run before its battery wears out is exponentially distributed with the average value of 100,000 miles. If a car manufacturer decides to install this type of battery to power the vehicle, do the following: 1) What percentage of the cars will fail at the end of 50,000 miles

Respuesta :

Answer:

The value is [tex]P(X = 50,000) = 6.07*10^{-6}[/tex]

Step-by-step explanation:

From the question we are told that

The average value is [tex]E(x) = 100000 \ miles[/tex]

Generally the exponential distribution function is mathematically represented as

[tex]f(x) = \{ \left \theta* e^{-\theta * x } \ ; \ \ \theta >0} \atop {0 \ ; \ otherwise }} \right.[/tex]

Here [tex]\theta [/tex] is a constant which is mathematically represented as

[tex]\theta = \frac{1}{E(x)}[/tex]

=> [tex]\theta = \frac{1}{100000}[/tex]

=> [tex]\theta =1 *10^{-5}[/tex]

So at x = 50,000 miles (given)

[tex]f(50000) = 1 *10^{-5} * e^{-1*10^{-5} * 50000}[/tex]

[tex]f(50000) = 6.07*10^{-6}[/tex]

So the percentage of the cars will fail at the end of 50,000 miles is

[tex]P(X = 50,000) = 6.07*10^{-6}[/tex]