Answer:
The answer is "96.864 ml".
Step-by-step explanation:
In this question, the formula of [tex]\bold{CI = X \pm t \times s}[/tex].
( where X is the mean, t is the coefficient, and s is the mean difference error)
As a result, only 2.5% of containers might include less than 100 ml of volume, its trust coefficient could indeed be used in accordance with 95%, which is [tex]t=1.96[/tex].
And it can take [tex]\pm \ 1.6 \ ml[/tex] to have been the full value the standard infinite: [tex]\to CI = 100 \pm (1.96 \times 1.6) \\\\[/tex]
[tex]= 100 \pm (3.136) \\\\[/tex]
Consequently, if the standard error is [tex]\pm \ 1.6 \ ml[/tex] , a similar amount should be used to fill
[tex]= 100 - 3.136 \\\\= 96.864 \ \ mL[/tex]
