Respuesta :

Answer:

Given -

  • Time taken by first tap = 4 hours.
  • Time taken by second tap = 6 hours.

Now, we'll calculate the work done by both the taps -

[tex] \\ \sf \: \frac{1}{4} + \frac{1}{6} \\ \\ \\ \bf \: lcm \: \: of \: \: 4 \: \: \& \: \: 6 = 12 \\ \\ \\ \implies \sf \: \frac{3 + 2}{12} \\ \\ \\ \implies \sf \frac{5}{12} \\ \\ [/tex]

Now, reciprocal it -

[tex] \\ \implies \sf \frac{12}{5} = 2 \frac{2}{5} \\ [/tex]

Therefore, time taken by both the taps will be 2 2/5 hours.

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