Find surface area of the regular pyramid plz help ASAP

Answer:
B. 3,157 in^2
Step-by-step explanation:
surface area of a pyramid shown = 3x lateral area + base area
given:
s1 = s2 = s3 = 42 in
L = 38 in
lateral area = ( 1/2 * 42 * 38 ) = 798 sq. in
base area = √3 * s^2
4
= √3 * 42^2
4
= 763.834 sq. in
therefore,
surface area of a pyramid shown = 3x 798 + 763.834 = 3,157 in^2
Answer:
= 3,157 in^2
Step-by-step explanation:
surface area = 3x lateral area + base area
given:
side lengths area s1 = s2 = s3 = 42 in
slant height = 38 in
lateral area = ( 1/2 * 42 * 38 )
= 798 sq. in
base area = (√3 * s^2 ) / 4
= (√3 * 42^2 ) / 4
= 763.83 sq. in
surface area = 3x 798 + 763.834
= 3,157 in^2