Step-by-step explanation:
Hey there!!!
Here,
Triangle BCM and triangle ABC are 2 isosceles triangle.
Solving in triangle BCM.
Angle CBM = 31° { it is the base angle.}
Angle CBM + 31° + angle BCM = 180° { sum of interior angle of a triangle is 180°}.
31°+31°+ angle BCM = 180°
Angle BCM = 180° - 62°
Therefore the measure of angle BCM = 118°.
Again,
Solving in triangle ABC.
Angle BCM + angle ACB = 180° { being linear pair}.
118°+ angle ACB = 180°
Angle ACB = 180°-118°
Therefore the measure of angle ACB is 62°.
Angle ACB = angle BAC (Base of an isosceles triangle).
Therefore the measure of angle BAC = 62°.
Now, To find x,
Angle BAC + angle ACB + angle x = 180° (sun of interior angle of a triangle is 180°).
62°+62°+angle x = 180°
Therefore the measure of angle x is 56°.
[tex]hope \: it \: helps...[/tex]
