Answer:
√
36
=
6
lies between consecutive odd integers
5
and
7
.
Step-by-step explanation:
"The" square root of
36
is itself an integer, namely
6
, since
6
2
=
36
. So it does not lie between consecutive integers.
It does lie between consecutive odd integers
5
and
7
.
Note that
36
has another square root, namely
−
6
, since
−
6
satisfies:
(
−
6
)
2
=
36
