If 1.136 × 10⁷ atoms of oxygen can fit across the head of a pin whose diameter is 1.5 × 10⁻³ m, the atomic radius of oxygen would be 6.60 × 10⁻¹¹ m.
The head of a pin is 1.5 × 10⁻³ m in diameter. If 1.136 × 10⁷ atoms of oxygen can fit across the head of a pin, the diameter of each oxygen atom would be:
[tex]\frac{1.5 \times 10^{-3}m }{1.136 \times 10^{7}atom} = 1.32 \times 10^{-10}m/atom[/tex]
The atomic radius of oxygen would be half of its diameter.
[tex]\frac{1.32 \times 10^{-10} m}{2} = 6.60 \times 10^{-11} m[/tex]
If 1.136 × 10⁷ atoms of oxygen can fit across the head of a pin whose diameter is 1.5 × 10⁻³ m, the atomic radius of oxygen would be 6.60 × 10⁻¹¹ m.
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