Respuesta :

nicoleischange

Answer:

40x=120

10r=130

Step-by-step explanation:

8(5x=15-5y)= 40x=120-40y

5(8y+26=2r)= 40y+130=10r

40x=120-40y

10r=130+40y

40x=120

10r=130

This is as far as I could get because the two numbers have two different variables, I couldn't subtract or add. It would be like subtracting apples from oranges... you can't

unicorn3125

   [tex]\begin{cases}5x=15-5y\\ 8y+26=2x\end{cases}\\\\\begin{cases}5x+5y=15\\ -2x+8y=-26\end{cases}\\\\\begin{cases}(5x+5y)\cdot2=15\cdot2\\ (-2x+8y)\cdot5=-26\cdot5\end{cases}[/tex]

+  [tex]\begin{cases}10x+10y=30\\ -10x+40y=-130\end{cases}[/tex]       (adding first equation to second)

   [tex]\begin{cases}10x+10y=30\\{}\qquad50y=-100\end{cases}\\\\\begin{cases}10x+10y=30\\{}\qquad y=-2\end{cases}\\\\\begin{cases}10x+10(-2)=30\\y=-2\end{cases}\\\\ \begin{cases}10x-20=30\\y=-2\end{cases}\\\\ \begin{cases}10x=50\\y=-2\end{cases}\\\\ \begin{cases}x=5\\y=-2\end{cases}[/tex]  

Otras preguntas