Answer:
3.44 metres
Explanation:
To determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E], resolve the given parameters into x - component and y - component.
Resolving into x - component
- 2.4cos32 + 4.9cos27 = 2.3306
Resolving into y - component
- 2.4sin32 - 4.9sin27 - 1.6 = - 2.553
The vector sum of the displacement will be
Sqrt( 2.3^2 + 2.6^2) =
Sqrt ( 11.81)
3.44 m
Therefore, the vector sum of the displacements is 3.44 metres
