The teacher spend some amount on buying costumes and microphones for 6 cast members.
GiveN:
- Cost of each costume = $38
- Cost of each microphone = $c
- Total money spent = $354
Let's frame the equation. Total money is the total amount spent for 6 cast members.
Money spent on costumes = $38 × 6
Money spent on microphone = $c × 6
Equation:
[tex]6 \times 38 + 6 \times c = 354[/tex]
Taking 6 as common,
[tex]6(38 + c) = 354[/tex]
Dividing 6 from both sides,
[tex] \dfrac{6(38 + c)}{6} = \dfrac{354}{6} [/tex]
[tex]38 + c = 59[/tex]
Solving further,
[tex]38 + c - 38 = 59 - 38[/tex]
[tex]c = 21[/tex]
So, the cost of each microphone = $21
The teacher spent this much on each microphone.
#CarryOnLearning
━━━━━━━━━━━━━━━━━━━━
