Given :
[tex]a_1=-25[/tex] .
[tex]a_n=a_{n-1}-14[/tex] .
To Find :
The general equation of [tex]a_n[/tex] .
Solution :
We know , when difference between any two consecutive terms in an A.P is equal , then the series is in arithmetic progression .
Now , common difference ,
[tex]d=a_n-a_{n-1}\\\\d=-14[/tex]
Also , first term is -25 .
Now , general term of an A.P is given by :
[tex]a_n=a+(n-1)d\\\\a_n=-25+(n-1)(-14)\\\\a_n=-25-14n+14\\\\a_n= -11-14n[/tex]
Hence , this is the required solution .
