Anurak has nickels, dimes, and pennies in his pocket. The coins in Anurak's pocket have a total value of 75 cents. He has three more nickels than dimes and five times as many pennies as dimes. How many coins of each type does Anurak have?

Respuesta :

Answer:

Anurak has 15 pennies, 6 nickels and 3 dimes.

Step-by-step explanation:

We must have these informations in mind:

1) A penny is a 1-cent coin.

2) A dime is a 10-cent coin.

3) A nickel is a 5-cent coin.

Let be [tex]x[/tex], [tex]y[/tex], [tex]z[/tex] the quantities of pennies, nickels and dimes, respectively. From statement we get that to value in Anurak's pocket is represented by this mathematical expression:

[tex]0.01\cdot x + 0.05 \cdot y + 0.10\cdot z = 0.75[/tex] (Eq. 1)

In addition, we get the following identities:

i) He has three more nickels than dimes

[tex]z + 3 = y[/tex] (Eq. 2)

ii) And five times as many pennies as dimes

[tex]x = 5\cdot z[/tex] (Eq. 3)

The system of linear equations is now reduced: (Eqs. 2, 3) in (Eq. 1)

[tex]0.05\cdot z +0.05\cdot z + 0.15 + 0.10\cdot z = 0.75[/tex]

[tex]0.20\cdot z = 0.60[/tex]

[tex]z = 3[/tex]

The remaining variables are [tex]y = 6[/tex] and [tex]x = 15[/tex].

Anurak has 15 pennies, 6 nickels and 3 dimes.

Answer:

Anurak has 15 pennies, 6 nickels and 3 dimes.

Step-by-step explanation: