5 Kari makes a kite in the form of a parallelogram, EDGF, as shown in the diagram. Its diagonals [DF] and [EG] intersect at point H. She plots the vertices on a coordinate system with the following coordinates:
D(3,6), G(1,3), H(4, y) and E(x, 6). Find the values of x and y.

5 Kari makes a kite in the form of a parallelogram EDGF as shown in the diagram Its diagonals DF and EG intersect at point H She plots the vertices on a coordin class=

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Answer:

The values of x and y are;

x = 7 and y = 4.5

Step-by-step explanation:

The question is a word problem, given that the shape of the kite Karl makes is a parallelogram

The coordinates of the vertices are;

D(3, 6), G(1, 3), H(4, y), and E(x, 6)

From the properties of a parallelogram we have;

The diagonals bisect each other

Therefore;

GH = EH = 1/2·GE

Therefore, we have;

The coordinates of the point H = The coordinate of the midpoint of the line EG

The coordinates of the midpoint of a line with end points, (x₁, y₁) and (x₂, y₂) is given as follows;

The coordinates of the midpoint of a line = ((x₁ + x₂)/2, (y₁ + y₂)/2)

Therefore;

The coordinates of the midpoint of the line EG  are ((1 + x)/2, (3 + 6)/2)

Given that the midpoint of EG is the point H and the coordinate of the point H is (4, y), we have;

(1 + x)/2 = 4, therefore;

2 × 4 = 1 + x

8 = 1 + x

x = 8 - 1 = 7

Similarly, we have from the coordinate of point H which is given as follows;

((1 + x)/2, (3 + 6)/2) = (4, y)

y = (3 + 6)/2 = 9/2 = 4.5

Therefore, x = 7, y = 4.5.

Parallel sides of a parallelogram have the same slope

The values of x and y are 6 and 3, respectively.

The coordinate points are given as:

[tex]\mathbf{D =(3,6)}[/tex]

[tex]\mathbf{G =(1,3)}[/tex]

[tex]\mathbf{H =(4,y)}[/tex]

[tex]\mathbf{E =(x,6)}[/tex]

Lines DG and HE are parallel.

This means that they have the same slope (m)

The slope is calculated as:

[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]

So, we have:

[tex]\mathbf{m_{DG} = \frac{3 - 6}{1 - 3}}[/tex]

[tex]\mathbf{m_{DG} = \frac{- 3}{- 2}}[/tex]

[tex]\mathbf{m_{DG} = \frac{3}{2}}[/tex]

Similarly

[tex]\mathbf{m_{HE} = \frac{6 - y}{x - 4}}[/tex]

The slopes are equal.

So, we have:

[tex]\mathbf{\frac{6 - y}{x - 4} = \frac 32}[/tex]

By comparison:

[tex]\mathbf{6 - y = 3}[/tex] and [tex]\mathbf{x - 4 = 2}[/tex]

Solve for y in [tex]\mathbf{6 - y = 3}[/tex]

[tex]\mathbf{y = 3}[/tex]

Solve for x in [tex]\mathbf{x - 4 = 2}[/tex]

[tex]\mathbf{x = 6}[/tex]

Hence, the values of x and y are 6 and 3, respectively.

Read more about parallelogram and slopes at:

https://brainly.com/question/19654204