Please help urgent easy question,just no 8
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Answer:
Ruby is 11. Tanya is 14.
Step-by-step explanation:
Let Ruby's age eight years ago be x.
Tanya's age eight years ago = 2x.
Ruby's age now = x + 8
Tanya's age now = 2x + 8
Total age = [tex]x+8+2x+8=25[/tex]
[tex]3x+16=25[/tex]
Subtract 16 from both sides:
[tex]3x+16-16=25-16[/tex]
[tex]3x=9[/tex]
Divide both sides by 3:
[tex]\frac{3x}{3} =\frac{9}{3}[/tex]
[tex]x=3[/tex]
Ruby's age now [tex]=x+8=3+8=11[/tex]
Tanya's age now [tex]=2x+8=2(3)+8=6+8=14[/tex]
Answer:
Tanya is 14; Ruby is 11.
Step-by-step explanation:
Let T represent Tanya's current age and let R represent Ruby's current age.
We know that their ages add up to 25. So:
[tex]T+R=25[/tex]
8 years ago, Tanya was twice as old as Ruby. In other words, Tanya's current age minus 8 is the same as Ruby's current age minus 8 times 2. So:
[tex]T-8=2(R-8)[/tex]
We have a system of equations. We can solve by substitution. From the first equation, subtract R from both sides:
[tex]T=25-R[/tex]
Substitute this into the second equation:
[tex](25-R)-8=2(R-8)[/tex]
On the left, subtract. On the right, distribute:
[tex]17-R=2R-16[/tex]
Add 16 to both sides. The right side cancels:
[tex]33-R=2R[/tex]
Add R to both sides. The left cancels:
[tex]33=3R[/tex]
Divide both sides by 3:
[tex]R=11[/tex]
So, Ruby is currently 11 years old.
So, Tanya is currently 25-11 or 14 years old.
Check:
8 years ago, Ruby was 11-8 or 3 years old.
8 years ago, Tanya is 14-8 or 6 years old.
Tanya's age of 6 is 2 times Ruby's age of 3 so our answer is correct.