Respuesta :

Answer:

Ruby is 11. Tanya is 14.

Step-by-step explanation:

Let Ruby's age eight years ago be x.

Tanya's age eight years ago = 2x.

Ruby's age now = x + 8

Tanya's age now = 2x + 8

Total age = [tex]x+8+2x+8=25[/tex]

[tex]3x+16=25[/tex]

Subtract 16 from both sides:

[tex]3x+16-16=25-16[/tex]

[tex]3x=9[/tex]

Divide both sides by 3:

[tex]\frac{3x}{3} =\frac{9}{3}[/tex]

[tex]x=3[/tex]

Ruby's age now [tex]=x+8=3+8=11[/tex]

Tanya's age now [tex]=2x+8=2(3)+8=6+8=14[/tex]

Answer:

Tanya is 14; Ruby is 11.

Step-by-step explanation:

Let T represent Tanya's current age and let R represent Ruby's current age.

We know that their ages add up to 25. So:

[tex]T+R=25[/tex]

8 years ago, Tanya was twice as old as Ruby. In other words, Tanya's current age minus 8 is the same as Ruby's current age minus 8 times 2. So:  

[tex]T-8=2(R-8)[/tex]

We have a system of equations. We can solve by substitution. From the first equation, subtract R from both sides:

[tex]T=25-R[/tex]

Substitute this into the second equation:

[tex](25-R)-8=2(R-8)[/tex]

On the left, subtract. On the right, distribute:

[tex]17-R=2R-16[/tex]

Add 16 to both sides. The right side cancels:

[tex]33-R=2R[/tex]

Add R to both sides. The left cancels:

[tex]33=3R[/tex]

Divide both sides by 3:

[tex]R=11[/tex]

So, Ruby is currently 11 years old.

So, Tanya is currently 25-11 or 14 years old.

Check:

8 years ago, Ruby was 11-8 or 3 years old.

8 years ago, Tanya is 14-8 or 6 years old.

Tanya's age of 6 is 2 times Ruby's age of 3 so our answer is correct.