Answer:
y = ± [tex]\sqrt{\frac{a-x}{2b} }[/tex]
Step-by-step explanation:
Given
x = a - 2by² ( subtract a from both sides )
x - a = - 2by² ( multiply through by - 1 to clear the leading negative )
a - x = 2by² ( divide both sides by 2b )
[tex]\frac{a-x}{2b}[/tex] = y² ( take the square root of both sides )
y = ± [tex]\sqrt{\frac{a-x}{2b} }[/tex]
Making y the subject of the formula, [tex]x = a - 2by^2[/tex] , the answer would be:
[tex]\mathbf{y = \sqrt{\frac{x - a}{-2b}} }[/tex]
Given the formula: [tex]x = a - 2by^2[/tex],
Required:
Making y the subject of the formula
This is done as shown below:
[tex]x = a - 2by^2[/tex]
[tex]x - a = - 2by^2[/tex]
[tex]\frac{x - a}{-2b} = y^2[/tex]
[tex]\sqrt{\frac{x - a}{-2b}} = y\\\\\\\mathbf{y = \sqrt{\frac{x - a}{-2b}} }[/tex]
Therefore, making y the subject of the formula, [tex]x = a - 2by^2[/tex] , the answer would be: [tex]\mathbf{y = \sqrt{\frac{x - a}{-2b}} }[/tex]
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https://brainly.com/question/19557491
