Can someone please please pleaseee helppp
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Step-by-step explanation:
Hey there!!!
Here,
The point is, (-3,1).
Using one point formula.
(y-1)= m(x+3)....1st equation.
It has said that it is also perpendicular to the line y = 1/3x + 2 .......2nd equation.
Now, the equation with y = mx + c.
We get slope (m2) = 1/3.
Now,
As per the condition of perpendicular lines,
[tex]m1 \: \times m2 = - 1[/tex]
[tex]m1 \times \frac{1}{3} = - 1[/tex]
Simplifying them we get,
m1 = -3.
Therefore the slope is -3.
Hope it helps...