Triangles given in Options (b) and (c) are similar.
Theorems of similar triangles:
- If two angles of a pair of triangles are equal in measure, then the triangles will be similar by A-A property.
- If corresponding sides of two triangles are proportional, both the triangles will be similar.
From the picture attached,
a). In triangle ABC,
∠A + ∠B + ∠C = 180° [By triangle sum theorem]
60° + ∠B + 40° = 180°
∠B = 80°
Similarly, in ΔDEF,
∠D + ∠E + ∠F = 180°
60° + 85° + ∠F = 180°
∠F = 35°
Since, measure of angles of both the triangles are different in measures, triangles will not be similar.
b). In ΔABC,
∠A + ∠B + ∠C = 180°
45° + 50° + ∠B = 180°
∠B = 85°
In ΔDEF,
∠D + ∠E + ∠F = 180°
50° + 85° + ∠F = 180°
∠F = 45°
Hence, ∠C ≅ ∠D, ∠A≅ ∠F and ∠B ≅ ∠E
Since, measure of corresponding angles are equal, both the
triangles (ΔABC ~ ΔFED) will be similar.
c). Here, corresponding sides of both the triangles are proportional,
[tex]\frac{AB}{DE}= \frac{CA}{FD}= \frac{BC}{EF}[/tex]
[tex]\frac{14}{7}= \frac{12}{6}= \frac{16}{8}[/tex]
[tex]\frac{2}{1}= \frac{2}{1}= \frac{2}{1}[/tex]
Both the triangles ΔABC and ΔDEF will be similar.
Therefore, Option B and Option C are the correct options.
Learn more about the similarity of two triangles here,
https://brainly.com/question/2499350?referrer=searchResults
