Answer:
The overall force pushing on the block is 26.63 N in the direction of N 34° E
Explanation:
Given;
force going north, F₁ = 15 N
force going east, F₂ = 22 N
The resultant of the two forces is the hypotenuse side of the right angled triangle formed by the two forces.
Let the magnitude of the resultant force = F
F² = F₁² + F₂²
F = √(F₁² + F₂²)
F = √(15² + 22²)
F = 26.63 N
The direction of the force is the angle between the resultant force and the horizontal force.
tan θ = 15 / 22
tan θ = 0.6818
θ = tan⁻¹ ( 0.6818)
θ = 34°
Therefore, the overall force pushing on the block is 26.63 N in the direction of N 34° E
