Suppose PR = 54, solve for QR
4x-1
3x-1
P
R

Answer:
[tex] QR = 23 [/tex]
Step-by-step explanation:
P, A, and R are collinear.
PR = 54
[tex] PQ = 4x - 1 [/tex]
[tex] QR = 3x - 1 [/tex]
To solve for the numerical length of PR, let's generate an equation to find the value of x.
According to the segment addition postulate:
[tex] PQ + QR = PR [/tex]
[tex] (4x - 1) + (3x - 1) = 54 [/tex] (substitution)
Solve for x
[tex] 4x - 1 + 3x - 1 = 54 [/tex]
Combine like terms
[tex] 4x + 3x - 1 - 1 = 54 [/tex]
[tex] 7x - 2 = 54 [/tex]
Add 2 to both sides
[tex] 7x - 2 + 2 = 54 + 2 [/tex]
[tex] 7x = 56 [/tex]
Divide both sides by 7
[tex] \frac{7x}{7} = \frac{56}{7} [/tex]
[tex] x = 8 [/tex]
[tex] QR = 3x - 1 [/tex]
Plug in the value of x into the equation
[tex] QR = 3(8) - 1 = 24 - 1 [/tex]
[tex] QR = 23 [/tex]