Answer: [tex]\frac{1}{\sqrt[3]{x} }[/tex]
Step-by-step explanation:
Since the base of the exponents are the same, we can go ahead and subtract the exponents.
[tex]\frac{x^{\frac{5}{6}} }{x^{\frac{7}{6} }}[/tex] [subtract exponents]
[tex]x^{-\frac{2}{6} }[/tex] [simplify exponent]
[tex]x^{-\frac{1}{3}}[/tex] [write in radical form]
[tex]\frac{1}{\sqrt[3]{x} }[/tex]
