Given:
Height of rectangle = 4 units
Area of rectangle up to 48 square units.
To find:
The inequality which represents all the possible lengths in units of the bases.
Solution:
Let the possible lengths in units of the bases be b.
Area of rectangle = Length × width
Here, Height of rectangle = width = 4 units. So, area of rectangle is
[tex]Area=b\times 4[/tex]
[tex]Area=4b[/tex]
Area of rectangle up to 48 square units. It means the area should be less than or equal to 48 square units.
[tex]4b\leq 48[/tex]
Divide both sides by 4.
[tex]b\leq \dfrac{48}{4}[/tex]
[tex]b\leq 12[/tex]
Length can not be negative or zero.
[tex]0<b\leq 12[/tex]
Therefore, the required inequality is [tex]0<b\leq 12[/tex].
Answer:
H) b ≤ 12
Step-by-step explanation:
48/4 = 12.
12 is the only one you can divide into 48 equally.
X 48 ÷ 192: Can't do
X 48 ÷ 44: Can't do
X 48 ÷ 52: Can't do
√ 48 ÷ 12 = 4
